Consider a solid slab (thermal conductivity, k=10 W/m.K) with thickness 0.2 m and of infinite extent in the other two directions. Surface 2, at 300 K, is exposed to a fluid flow at a free stream temperature (T∞) of 293 K, with a convective heat transfer coefficient (h) of 100 W·m⁻²·K⁻¹. Surface 2 is opaque, diffuse and gray with an emissivity (ε) of 0.5 and exchanges heat by radiation with very large surroundings at 0 K. Radiative heat transfer inside the solid slab is neglected. The Stefan-Boltzmann constant is 5.67×10⁻⁸ W·m⁻²·K⁻⁴. The temperature T1 of Surface 1 of the slab, under steady-state conditions, is _________ K (round off to the nearest integer).
Explanation
At steady state, conduction from surface 1 to 2 equals convection + radiation leaving surface 2: k(T1−T2)/L = h(T2−T∞) + εσT2⁴. Convective flux = 100×(300−293)=700 W/m². Radiative flux = 0.5×5.67×10⁻⁸×300⁴ ≈229.6 W/m². Total = 929.6 W/m². So T1 = T2 + (929.6×0.2)/10 = 300+18.6 ≈ 319 K.
Source: GATE ME 2022 Session 1 (ME-1) (2022)
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