Project ForgeA steel spur pinion has module m=1.25 mm, 20 teeth, and 20° pressure angle. The pinion rotates at 1200 rpm and transmits power to a 60-teeth gear. The face width F=50 mm, Lewis form factor Y=0.322, and dynamic factor Kv=1.26. Using the Lewis formula σ = KvW^t/(FmY), if the maximum bending stress experienced by the pinion is 400 MPa, the power transmitted is __________ kW (round off to one decimal place).
Explanation
W^t=σFmY/Kv=400×50×1.25×0.322/1.26≈6389 N. Pitch diameter d=mT=1.25×20=25mm. Pitch line velocity v=πdN/60=π×0.025×1200/60≈1.571 m/s. Power=W^t×v≈6389×1.571≈10,036 W≈10.0 kW.
Source: GATE ME 2020 Session 2 (ME-2) (2020)
This question is part of a 15-day revision cycle — sign in and Project Forge will bring it back the day before you'd forget it.