Project ForgeIn a cam-follower, the follower rises by h as the cam rotates by δ (radians) at constant angular velocity ω (radians/s). The follower is uniformly accelerating during the first half of the rise period and uniformly decelerating in the latter half. Assuming the magnitudes of the acceleration and deceleration are the same, the maximum velocity of the follower is
- A4hω/δ
- Bhω
- 2hω/δ
- D2hω
Explanation
The rise takes total time t=δ/ω, and the velocity profile is triangular (linear ramp up then down, symmetric). For a displacement h covered in time t under a triangular velocity profile, the peak (maximum) velocity is Vmax = 2h/t = 2h/(δ/ω) = 2hω/δ.
Source: GATE ME 2018 Session 2 (Set 2) (2018)
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