Project ForgeFluid Mechanics
Bernoulli's Equation & Flow
GATE 2018
Medium
A tank open at the top with a water level of 1 m has a hole at a height of 0.5 m. A free jet leaves horizontally from the smooth hole. The distance X (in m) where the jet strikes the floor is
- A0.5
- 1.0
- C2.0
- D4.0
Explanation
Exit velocity from Torricelli's law: v=√(2g·h1), h1=0.5 m (head above hole). Fall time from height h2=0.5 m: t=√(2h2/g). Range X=v·t=√(2g·h1)×√(2h2/g)=2√(h1·h2)=2√(0.5×0.5)=2×0.5=1.0 m.
Source: GATE ME 2018 Session 1 (Set 1) (2018)
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