Project ForgeThermodynamics
First Law of Thermodynamics
GATE 2017
Easy
The volume and temperature of air (assumed to be an ideal gas) in a closed vessel is 2.87 m³ and 300 K, respectively. The gauge pressure indicated by a manometer fitted to the wall of the vessel is 0.5 bar. If the gas constant of air is R=287 J/kg·K and the atmospheric pressure is 1 bar, the mass of air (in kg) in the vessel is
- A1.67
- B3.33
- 5.00
- D6.66
Explanation
Absolute pressure = 1+0.5 = 1.5 bar = 150,000 Pa. m = pV/(RT) = (150000×2.87)/(287×300) = 430500/86100 = 5.0 kg.
Source: GATE ME 2017 Session 2 (ME-2) (2017)
This question is part of a 15-day revision cycle — sign in and Project Forge will bring it back the day before you'd forget it.