Project ForgeSign up free
General Aptitude
Quantitative Aptitude
GATE 2016
Hard

S, M, E and F are working in shifts in a team to finish a project. M works with twice the efficiency of others but for half as many days as E worked. S and M have 6 hour shifts in a day, whereas E and F have 12 hours shifts. What is the ratio of contribution of M to contribution of E in the project?

  • A1:1
  • 1:2
  • C1:4
  • D2:1

Explanation

Let E and F's efficiency be e (M's is 2e), and let E work d days. M works d/2 days (half of E's days). M's contribution = 2e x 6 hr/day x (d/2) days = 6e x d. E's contribution = e x 12 hr/day x d days = 12e x d. Ratio M:E = 6ed : 12ed = 1:2.

Source: GATE ME 2016 Set-3 (2016)

This question is part of a 15-day revision cycle — sign in and Project Forge will bring it back the day before you'd forget it.

Start revising free