Project ForgeSign up free
Manufacturing Engineering
Machining Processes
GATE 2016
Hard

The tool life equation for an HSS tool is VT^0.14 f^0.7 d^0.4 = Constant. A tool life T=30 min is obtained with V=45 m/min, f=0.35 mm, d=2.0 mm. If V, f, and d are each increased by 25%, the tool life (in min) is

  • A0.15
  • 1.06
  • C22.50
  • D30.0

Explanation

With V,f,d all scaled by 1.25: 1.25^(1+0.7+0.4) × T_new^0.14 = T_old^0.14 → T_new = T_old / 1.25^(2.1/0.14) = 30/1.25^15 ≈ 30/28.4 ≈ 1.06 min.

Source: GATE ME 2016 Set-1 (2016)

This question is part of a 15-day revision cycle — sign in and Project Forge will bring it back the day before you'd forget it.

Start revising free