Project ForgeGeneral Aptitude
Quantitative Aptitude
GATE 2015
Medium
Ram and Ramesh appeared in an interview for two vacancies in the same department. The probability of Ram's selection is 1/6 and that of Ramesh is 1/8. What is the probability that only one of them will be selected?
- A47/48
- 1/4
- C13/48
- D35/48
Explanation
P(only Ram) = P(Ram)*P(not Ramesh) = (1/6)*(7/8) = 7/48. P(only Ramesh) = P(not Ram)*P(Ramesh) = (5/6)*(1/8) = 5/48. P(exactly one selected) = 7/48 + 5/48 = 12/48 = 1/4.
Source: GATE ME 2015 (Session 1) (2015)
This question is part of a 15-day revision cycle — sign in and Project Forge will bring it back the day before you'd forget it.