General Aptitude
Quantitative Aptitude
GATE 2013
Medium
A tourist covers half of his journey by train at 60 km/h, half of the remainder by bus at 30 km/h and the rest by cycle at 10 km/h. The average speed of the tourist in km/h during his entire journey is
- A36
- B30
- 24
- D18
Explanation
Let total distance = D. Train covers D/2 at 60 km/h (time = D/120). The remainder D/2 splits evenly: bus covers D/4 at 30 km/h (time = D/120), cycle covers D/4 at 10 km/h (time = D/40 = 3D/120). Total time = D/120 + D/120 + 3D/120 = 5D/120 = D/24. Average speed = D / (D/24) = 24 km/h.
Source: GATE ME 2013 (Booklet Code A) (2013)
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