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Manufacturing Engineering
Machining Processes
GATE 2013
Medium

For the same orthogonal turning operation described above (100 mm diameter bar, feed 0.25 mm/rev, depth of cut 4 mm, cutting velocity 90 m/min, tangential cutting force 1500 N perpendicular to the friction force, giving a rake angle of zero), the normal force acting at the chip-tool interface in N is

  • A1000
  • 1500
  • C2000
  • D2500

Explanation

With rake angle α=0, the standard force transformation N=Fc·cosα−Ft·sinα simplifies to N=Fc (since cos0=1, sin0=0), regardless of the (unknown) thrust force Ft. So N=Fc=1500 N.

Source: GATE ME 2013 (Booklet Code A) (2013)

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