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Thermodynamics
First Law of Thermodynamics
GATE 2012
Medium

Air enters an adiabatic nozzle at 300 kPa, 500 K with a velocity of 10 m/s. It leaves the nozzle at 100 kPa with a velocity of 180 m/s. The inlet area is 80 cm². The specific heat of air Cp is 1008 J/kg.K. The exit temperature of the air is

  • A516 K
  • B532 K
  • 484 K
  • D468 K

Explanation

For an adiabatic nozzle with no work: h1+V1²/2 = h2+V2²/2, so Cp(T1−T2) = (V2²−V1²)/2. T1−T2 = (180²−10²)/(2×1008) = 32300/2016 = 16.02 K. T2 = 500−16.02 ≈ 484 K.

Source: GATE ME 2012 (Booklet Code A) (2012)

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