Engineering Mathematics
Calculus
GATE 2011
Medium
The integral of 1/x from 1 to 3, when evaluated by using Simpson's 1/3 rule on two equal subintervals each of length 1, equals
- A1.000
- B1.098
- 1.111
- D1.120
Explanation
x0=1,x1=2,x2=3; f(x)=1/x gives f0=1, f1=0.5, f2=1/3. Simpson's 1/3 rule: (h/3)[f0+4f1+f2]=(1/3)[1+2+0.3333]=(1/3)(3.3333)=1.111.
Source: GATE ME 2011 (2011)
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