Project ForgeEngineering Mathematics
Calculus
GATE 2009
Medium
The area enclosed between the curves y²=4x and x²=4y is
- 16/3
- B8
- C32/3
- D16
Explanation
The parabolas intersect at (0,0) and (4,4). Area=∫0^4[√(4x)-x²/4]dx=∫0^4[2√x-x²/4]dx=[(4/3)x^1.5-x³/12] from 0 to 4=32/3-16/3=16/3.
Source: GATE ME 2009 (2009)
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