Project ForgeEngineering Mathematics
Calculus
GATE 2008
Medium
Let f=yˣ. What is ∂²f/∂x∂y at x=2, y=1?
- A0
- Bln2
- 1
- D1/ln2
Explanation
∂f/∂x=yˣ ln y. ∂²f/∂x∂y=x·y^(x-1)·ln y+y^(x-1). At x=2,y=1: ln1=0 and y^(x-1)=1, so ∂²f/∂x∂y=2(1)(0)+1=1.
Source: GATE ME 2008 (2008)
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