Project ForgeSign up free
Manufacturing Engineering
Machining Processes
GATE 2007
Medium

In orthogonal turning of a low carbon steel bar of diameter 150 mm with an uncoated carbide tool, the cutting velocity is 90 m/min. The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm. If the orthogonal rake angle is zero and the principal cutting edge angle is 90°, the shear angle in degrees is

  • A20.56
  • 26.56
  • C30.56
  • D36.56

Explanation

Chip thickness ratio r=t1/t2=0.24/0.48=0.5. With rake angle α=0: tanφ=r cosα/(1−r sinα)=0.5/1=0.5, φ=arctan(0.5)≈26.56°.

Source: GATE ME 2007 (2007)

This question is part of a 15-day revision cycle — sign in and Project Forge will bring it back the day before you'd forget it.

Start revising free