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Question

Consider the following function implemented in C:

void printxy(int x, int y) {
  int *ptr;
  x = 0;
  ptr = &x;
  y = *ptr;
  *ptr = 1;
  printf("%d,%d", x, y);
}

The output of invoking printxy(1,1) is

Accepted Answer

The correct answer is (C) 1,0. x is set to 0. ptr now points at x. y = *ptr reads x's current value, 0, into y. *ptr = 1 then sets x back to 1 (through the pointer). At the printf, x=1 and y=0, so the output is '1,0'.

Explanation