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Fluid Mechanics
Flow Through Pipes
GATE 2016
Medium

For turbulent flow through a smooth pipe, f=mRe^(−0.2). Water at 1m/s gives a frictional pressure drop of 10kPa. What is the pressure drop (kPa) at 2m/s?

  • A11.5
  • B20
  • 34.8
  • D40

Explanation

ΔP∝f·V²∝Re^(−0.2)·V²∝V^1.8 (since Re∝V). ΔP2=10×2^1.8=10×3.482=34.8 kPa.

Source: GATE CH 2016 (2016)

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