Process Calculations
Laws of Thermodynamics
GATE 2015
Hard
Match the derivative in the left column with its physical meaning: P=−(∂u/∂v)_s, Q=(∂g/∂P)_T, R=−(∂g/∂T)_P, S=(∂u/∂s)_v. Right column: I-Temperature, II-Pressure, III-v, IV-s. The correct combination is
- P-II, Q-III, R-IV, S-I
- BP-II, Q-IV, R-III, S-I
- CP-I, Q-IV, R-II, S-III
- DP-III, Q-II, R-IV, S-I
Explanation
From du=Tds−Pdv: −(∂u/∂v)_s=P (II), (∂u/∂s)_v=T (I). From dg=−sdT+vdP: (∂g/∂P)_T=v (III), −(∂g/∂T)_P=s (IV). So P-II, Q-III, R-IV, S-I.
Source: GATE CH 2015 (2015)
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